Which one of the following is most effective | vedclass

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(B) $As_2S_3$ is a negatively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of the

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$AlCl_3$

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(B) $As_2S_3$ is a negatively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particles. Since $As_2S_3$ is a negative sol, the positive ions (cations) are responsible for coagulation. The coagulating power increases with the increase in the valency of the cation. The valencies of the cations in the given options are: $K^+$ $(KCl)$, $Mg^{2+}$ $(MgSO_4)$, $Al^{3+}$ $(AlCl_3)$. Since $Al^{3+}$ has the highest valency $(+3)$, it is the most effective in causing the coagulation of the $As_2S_3$ sol.

List-$I$	List-$II$
$A$. Lyophilic colloid	$I$. Liquid-liquid colloid
$B$. Emulsion	$II$. Protective colloid
$C$. Positively charged colloid	$III$. $FeCl_3 + NaOH$
$D$. Negatively charged colloid	$IV$. $FeCl_3 + \text{hot water}$

Which one of the following is most effective in causing the coagulation of an $As_2S_3$ sol?

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