Which one of the following is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Paramagnetic substances contain one or more unpaired electrons.According to Molecular Orbital Theory $(MOT)$:$N_2$ (total $14$ electrons): $({\sig

Vedclass · Accepted Answer

$NO$

Vedclass · Answer

(B) Paramagnetic substances contain one or more unpaired electrons.According to Molecular Orbital Theory $(MOT)$:$N_2$ (total $14$ electrons): $({\sigma}1s)^2 ({\sigma}^*1s)^2 ({\sigma}2s)^2 ({\sigma}^*2s)^2 ({\pi}2p_x)^2 ({\pi}2p_y)^2 ({\sigma}2p_z)^2$. All electrons are paired, so it is diamagnetic.$NO$ (total $15$ electrons): $({\sigma}1s)^2 ({\sigma}^*1s)^2 ({\sigma}2s)^2 ({\sigma}^*2s)^2 ({\sigma}2p_z)^2 ({\pi}2p_x)^2 ({\pi}2p_y)^2 ({\pi}^*2p_x)^1$. It has one unpaired electron in the antibonding ${\pi}^*$ orbital, so it is paramagnetic.$CO$ (total $14$ electrons): Similar to $N_2$, it is diamagnetic.$O_3$ (total $24$ electrons): It is a diamagnetic molecule.Therefore, $NO$ is the correct answer.

Similar Questions

What is the bond order in $N_2^{+}$?

The bond order of $NO$ molecule is

When the reaction $O_2 + e^- \to O_2^-$ occurs,identify the molecular orbital into which the electron is added.

Which of the following is correctly matched?

The bond order of $O_2^+$ is the same as in

Vedclass Test Series

Exam Paper Generator

Online Exam Module