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(D) To obtain the maximum percentage of the terminal alkene (Hoffman product) in a dehydrohalogenation reaction,a bulky base is required. Steric hindr

Vedclass · Accepted Answer

Potassium alkoxide derived from $3$-ethyl-$3$-pentanol in $HO^{-}C(C_2H_5)_3$

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(D) To obtain the maximum percentage of the terminal alkene (Hoffman product) in a dehydrohalogenation reaction,a bulky base is required. Steric hindrance prevents the base from abstracting a proton from the more substituted $\beta$-carbon,favoring the abstraction of a proton from the less substituted $\beta$-carbon. Among the given options,the potassium alkoxide derived from $3$-ethyl-$3$-pentanol,which is $(C_2H_5)_3CO^-K^+$,is the bulkiest base. Therefore,it will yield the highest percentage of the terminal alkene.

Column-$I$	Column-$II$
$(i)$ $R-Cl + NaI \xrightarrow{\text{dry acetone}} R-I + NaCl$	$(a)$ Swarts reaction
$(ii)$ $CH_3-Br + AgF \xrightarrow{\Delta} CH_3-F + AgBr$	$(b)$ Wurtz reaction
$(iii)$ $R-X + Mg$ $\xrightarrow{\text{dry ether}} R-Mg-X$ $\xrightarrow{H_2O} RH + Mg(OH)X$	$(c)$ Finkelstein reaction
	$(d)$ Grignard reaction

Which one of the following is used to obtain the maximum percentage of terminal alkene by dehydrohalogenation of $CH_3CH_2C(CH_3)_2Br$?

Similar Questions

Identify the correct order of reactivity for the reaction with alcoholic $KOH$ for the following compounds:
$(a)$ $2$-bromo-$2,3$-dimethylbutane
$(b)$ $2$-chlorobutane
$(c)$ $2$-bromobutane
$(d)$ $1$-bromopropane

The product $X$ is
[Image: $1-$chloro$-1-$($2$-chloroethyl)cyclopentane] $\xrightarrow{LiBr/DMSO, S_N2 \text{ conditions}}$ Major product $(X)$

What product is formed when $1-$chlorobutane reacts with alcoholic $KOH$?

The decreasing order of the rate of $S_{N^1}$ reaction for the following compounds is:
$I$. $Ph-C(Br)(CH_3)-Ph$
$II$. $Ph-CH(Br)-Ph$
$III$. $Ph-CH(Br)-CH_3$
$IV$. $Ph-CH_2Br$

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