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(A) Two solutions are isotonic if they have the same osmotic pressure,i.e.,$\pi_1 = \pi_2$. Since $\pi = iCRT$,at the same temperature,the condition f

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$1 \ M \ NaCl$ and $2 \ M$ Urea

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(A) Two solutions are isotonic if they have the same osmotic pressure,i.e.,$\pi_1 = \pi_2$. Since $\pi = iCRT$,at the same temperature,the condition for isotonic solutions is $i_1 C_1 = i_2 C_2$,where $i$ is the van't Hoff factor and $C$ is the molar concentration. For $1.5 \ M \ AlCl_3$: $i = 4$ (dissociates into $Al^{3+} + 3Cl^-$),so $i_1 C_1 = 4 	imes 1.5 = 6.0$. For $1 \ M \ Na_2SO_4$: $i = 3$ (dissociates into $2Na^+ + SO_4^{2-}$),so $i_2 C_2 = 3 	imes 1 = 3.0$. Checking option $C$: $1.5 \ M \ AlCl_3$ $(i=4)$ gives $6.0$ and $1 \ M \ Na_2SO_4$ $(i=3)$ gives $3.0$. Wait,let us re-evaluate. Actually,for $1 \ M \ Na_2SO_4$,$i=3$,$iC = 3$. For $1.5 \ M \ AlCl_3$,$i=4$,$iC = 6$. Let us check the options again. $1 \ M \ NaCl$ $(i=2, iC=2)$ and $2 \ M$ Urea $(i=1, iC=2)$. Since $i_1 C_1 = i_2 C_2 = 2$,the pair in option $A$ is isotonic.

Which one of the following pairs of solutions will be isotonic at the same temperature?

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