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(B) The reaction of $1-$butene $(CH_3CH_2CH=CH_2)$ with $HBr$ follows Markovnikov's rule.According to Markovnikov's rule,the negative part of the adde

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(B) The reaction of $1-$butene $(CH_3CH_2CH=CH_2)$ with $HBr$ follows Markovnikov's rule.According to Markovnikov's rule,the negative part of the addendum $(Br^-)$ attaches to the carbon atom with fewer hydrogen atoms.Therefore,$CH_3CH_2CH=CH_2 + HBr \rightarrow CH_3CH_2CH(Br)CH_3$ ($2-$bromobutane).Reaction $(1)$ gives a mixture of $2-$bromopentane and $3-$bromopentane.Reaction $(3)$ gives $2,3-$dibromobutane.Reaction $(4)$ follows anti-Markovnikov addition,yielding $1-$bromobutane.

List-$I$	List-$II$
$(A)$ Sandmeyer reaction	$(I)$ $R-I$
$(B)$ Finkelstein reaction	$(II)$ $R-F$
$(C)$ Swarts reaction	$(III)$ $Ar-Br$
	$(IV)$ $R-Br$

Which one of the following reactions would be the best for the formation of $2-$bromobutane?
$(1)$ $CH_3CH=CHCH_2CH_3$ $\xrightarrow{HBr}$
$(2)$ $CH_3CH_2CH=CH_2$ $\xrightarrow{HBr}$
$(3)$ $CH_3CH=CHCH_3$ $\xrightarrow{Br_2}$
$(4)$ $CH_3CH_2CH=CH_2$ $\xrightarrow[Peroxide]{HBr}$

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Match the following reactions in List-$I$ with the products obtained in List-$II$:
List-$I$ List-$II$
$(A)$ Sandmeyer reaction $(I)$ $R-I$
$(B)$ Finkelstein reaction $(II)$ $R-F$
$(C)$ Swarts reaction $(III)$ $Ar-Br$
$(IV)$ $R-Br$

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Which one of the following reactions would be the best for the formation of $2-$bromobutane?$(1)$ $CH_3CH=CHCH_2CH_3$ $\xrightarrow{HBr}$$(2)$ $CH_3CH_2CH=CH_2$ $\xrightarrow{HBr}$$(3)$ $CH_3CH=CHCH_3$ $\xrightarrow{Br_2}$$(4)$ $CH_3CH_2CH=CH_2$ $\xrightarrow[Peroxide]{HBr}$