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(D) $p-n$ junction diode is said to be forward-biased if the potential at the $p$-side $(V_p)$ is higher than the potential at the $n$-side $(V_n)$,i.

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(D) $p-n$ junction diode is said to be forward-biased if the potential at the $p$-side $(V_p)$ is higher than the potential at the $n$-side $(V_n)$,i.e.,$V_p > V_n$.Let us analyze each option:$A$: $V_p = -4 	ext{ V}$,$V_n = -3 	ext{ V}$. Here,$-4 $B$: $V_p = -2 	ext{ V}$,$V_n = +2 	ext{ V}$. Here,$-2 $C$: $V_p = 3 	ext{ V}$,$V_n = 5 	ext{ V}$. Here,$3 $D$: $V_p = 0 	ext{ V}$,$V_n = -2 	ext{ V}$. Here,$0 > -2$,so $V_p > V_n$ (Forward biased).Therefore,option $D$ represents a forward-biased diode.

Which one of the following represents a forward-biased diode?

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