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(B) The electropositive character (metallic character) of an element increases down a group and decreases across a period from left to right. Among th

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$[Xe] \, 6s^1$

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(B) The electropositive character (metallic character) of an element increases down a group and decreases across a period from left to right. Among the given options,$[He] \, 2s^1$ is Lithium $(Li)$,$[Xe] \, 6s^1$ is Cesium $(Cs)$,$[He] \, 2s^2$ is Beryllium $(Be)$,and $[Xe] \, 6s^2$ is Barium $(Ba)$. Cesium $(Cs)$ is an alkali metal located at the bottom of the alkali metal group (Group $1$),making it the most electropositive element among the choices provided. Therefore,the correct configuration is $[Xe] \, 6s^1$.

Which one of the following represents the electronic configuration of the most electropositive element?

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