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(C) The paramagnetic property of an ion is directly proportional to the number of unpaired electrons present in its $d$-orbitals. $Cu^{2+} = [Ar] 3d^9

Vedclass · Accepted Answer

$Cu^{2+} < V^{2+} < Cr^{2+} < Mn^{2+}$

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(C) The paramagnetic property of an ion is directly proportional to the number of unpaired electrons present in its $d$-orbitals. $Cu^{2+} = [Ar] 3d^9$,number of unpaired electrons = $1$. $V^{2+} = [Ar] 3d^3$,number of unpaired electrons = $3$. $Cr^{2+} = [Ar] 3d^4$,number of unpaired electrons = $4$. $Mn^{2+} = [Ar] 3d^5$,number of unpaired electrons = $5$. Comparing the number of unpaired electrons $(1 < 3 < 4 < 5)$,the correct order of increasing paramagnetic property is $Cu^{2+} < V^{2+} < Cr^{2+} < Mn^{2+}$.

Which one of the following sets correctly represents the increase in the paramagnetic property of the ions?

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