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(D) Vanadium exhibits common oxidation states of $+2, +3, +4,$ and $+5$ in aqueous solutions. In $VO_2^+$,the oxidation state of $V$ is $+5$. In $VO^{

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$VO_2^{2+}$

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(D) Vanadium exhibits common oxidation states of $+2, +3, +4,$ and $+5$ in aqueous solutions. In $VO_2^+$,the oxidation state of $V$ is $+5$. In $VO^{2+}$,the oxidation state of $V$ is $+4$. In $[V(H_2O)_6]^{3+}$,the oxidation state of $V$ is $+3$. In $VO_2^{2+}$,the oxidation state of $V$ would be $+6$. Since the maximum oxidation state of vanadium is $+5$,the species $VO_2^{2+}$ is not stable or formed in aqueous solution.

Which one of the following species does not represent a cationic species of vanadium formed in an aqueous solution?

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