Which one of the following statements is WRON | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The cut-off wavelength $(\lambda_{min})$ of continuous $X-$rays is given by the formula $\lambda_{min} = \frac{hc}{eV}$, where $h$ is Planck's con

Vedclass · Accepted Answer

Cut-off wavelength of the continuous $X-$rays depends on the atomic number of the target.

Vedclass · Answer

(B) The cut-off wavelength $(\lambda_{min})$ of continuous $X-$rays is given by the formula $\lambda_{min} = \frac{hc}{eV}$, where $h$ is Planck's constant, $c$ is the speed of light, $e$ is the charge of an electron, and $V$ is the accelerating potential difference.This formula shows that $\lambda_{min}$ depends only on the accelerating voltage $V$ (which determines the energy of the electrons) and fundamental constants.It does not depend on the atomic number $(Z)$ of the target material.Therefore, the statement that the cut-off wavelength depends on the atomic number of the target is $WRONG$.

Which one of the following statements is $WRONG$ in the context of $X-$rays generated from an $X-$ray tube?

Similar Questions

Each of the roots of the equation $x^3-6x^2+6x-5=0$ is increased by $h$. If the new transformed equation does not contain the $x^2$ term,then $h$ is equal to:

The $P-V$ diagram of $2\,g$ of helium gas for a certain process $A \to B$ is shown in the figure. What is the heat given to the gas during the process $A \to B$ (in $,P_0V_0$)?

The sulphate of a metal $M$ contains $9.87 \%$ of $M$. This sulphate is isomorphous with $ZnSO_4 \cdot 7 H_2 O$. The atomic weight of $M$ is (in $.3$)

$A$ small sphere oscillates simple harmonically in a watch glass whose radius of curvature is $1.6 \ m$. The period of oscillation of the sphere in seconds is (acceleration due to gravity,$g = 10 \ m/s^2$). (in $\pi$)

$A$ magnetized wire of magnetic moment $M$ and length $L$ is bent into an arc of a circle subtending an angle of $60^{\circ}$ at the center. The new magnetic moment is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module