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(C) The reaction of $CH_3MgI$ with ethylene oxide (oxirane) follows a nucleophilic ring-opening mechanism. $CH_3MgI$ acts as a nucleophile $(CH_3^-)$

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Ethylene oxide

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(C) The reaction of $CH_3MgI$ with ethylene oxide (oxirane) follows a nucleophilic ring-opening mechanism. $CH_3MgI$ acts as a nucleophile $(CH_3^-)$ and attacks the less hindered carbon of the ethylene oxide ring. The resulting alkoxide intermediate,$CH_3-CH_2-CH_2-OMgI$,upon acidic hydrolysis,yields a primary alcohol,$CH_3-CH_2-CH_2-OH$ (propan$-1-$ol). Reaction: $CH_2-CH_2(O) + CH_3MgI$ $\rightarrow CH_3-CH_2-CH_2-OMgI$ $\xrightarrow{H_2O/H^+} CH_3-CH_2-CH_2-OH + Mg(OH)I$.

Which one of the following will produce a primary alcohol by reacting with $CH_3MgI$?

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