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(C) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$ and the concentration of the solute particle

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$0.1 \ M$ barium chloride

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(C) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$ and the concentration of the solute particles. The formula is $\Delta T_b = i 	imes K_b 	imes m$. $1$. For $0.1 \ M$ glucose (non-electrolyte),$i = 1$,so effective concentration = $0.1 	imes 1 = 0.1 \ M$. $2$. For $0.2 \ M$ sucrose (non-electrolyte),$i = 1$,so effective concentration = $0.2 	imes 1 = 0.2 \ M$. $3$. For $0.1 \ M$ barium chloride $(BaCl_2 ightarrow Ba^{2+} + 2Cl^-)$,$i = 3$,so effective concentration = $0.1 	imes 3 = 0.3 \ M$. $4$. For $0.1 \ M$ magnesium sulphate $(MgSO_4 ightarrow Mg^{2+} + SO_4^{2-})$,$i = 2$,so effective concentration = $0.1 	imes 2 = 0.2 \ M$. Since $BaCl_2$ provides the highest effective concentration of particles $(0.3 \ M)$,it will produce the maximum elevation in boiling point.

Which one of the following would produce maximum elevation in boiling point?

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