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(D) The rules for quantum numbers are as follows:$1$. The principal quantum number $(n)$ can be any positive integer $(1, 2, 3, \dots)$.$2$. For a giv

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(D) The rules for quantum numbers are as follows:$1$. The principal quantum number $(n)$ can be any positive integer $(1, 2, 3, \dots)$.$2$. For a given $n$,the azimuthal quantum number $(l)$ can have values from $0$ to $(n-1)$.$3$. For a given $l$,the magnetic quantum number $(m)$ can have values from $-l$ to $+l$,including $0$.Evaluating the options:- Option $A$: For $n=1$,$l$ can be $0$. For $l=0$,$m$ can be $0$. This set is correct.- Option $B$: For $n=2$,$l$ can be $0$ or $1$. If $l=0$,$m=0$. If $l=1$,$m=-1, 0, +1$. This set is correct.- Option $C$: For $n=3$,$l$ can be $0, 1, 2$. If $l=0$,$m=0$. If $l=1$,$m=-1, 0, +1$. If $l=2$,$m=-2, -1, 0, +1, +2$. This set is correct.Since all provided sets follow the rules of quantum mechanics,the correct answer is $D$.

Which one of the following sets of quantum numbers is incorrect?

Principal quantum number $(n)$ Azimuthal quantum number $(l)$ Magnetic quantum number $(m)$

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Which one of the following sets of quantum numbers is incorrect? Principal quantum number $(n)$ Azimuthal quantum number $(l)$ Magnetic quantum number $(m)$