Which of the following orders are correct?(I) | vedclass

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(A) $(I)$ Thermal stability of alkaline earth metal sulfates increases down the group as the size of the cation increases,making the $M-O$ bond weaker

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$(I), (IV)$

Vedclass · Answer

(A) $(I)$ Thermal stability of alkaline earth metal sulfates increases down the group as the size of the cation increases,making the $M-O$ bond weaker and the sulfate ion more stable. Thus,$BeSO_4 $(II)$ Basic nature of oxides increases down the group. $BeO$ is amphoteric,while $MgO$ and $CaO$ are basic. The correct order is $BeO $(III)$ Solubility of group $1$ hydroxides increases down the group due to the decrease in lattice energy being more significant than the decrease in hydration energy. The correct order is $LiOH $(IV)$ Melting point of alkali metal halides depends on lattice energy. $LiCl$ has high covalent character due to polarization,leading to a lower melting point than expected. The correct order is $NaCl > KCl > RbCl > CsCl > LiCl$. Thus,$(IV)$ is correct.

Which of the following orders are correct?
$(I)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$
$(II)$ Basic nature: $ZnO > BeO > MgO > CaO$
$(III)$ Solubility in water: $LiOH > NaOH > KOH > RbOH$
$(IV)$ Melting point: $NaCl > KCl > RbCl > CsCl > LiCl$

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Which orders are correct?
$(I)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$
$(II)$ Basic nature: $CaO > MgO > BeO > ZnO$
$(III)$ Solubility in water: $LiOH < NaOH < KOH < RbOH$
$(IV)$ Melting point: $NaCl > KCl > RbCl > CsCl > LiCl$

Select the incorrect order.

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Which of the following orders are correct?$(I)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$$(II)$ Basic nature: $ZnO > BeO > MgO > CaO$$(III)$ Solubility in water: $LiOH > NaOH > KOH > RbOH$$(IV)$ Melting point: $NaCl > KCl > RbCl > CsCl > LiCl$