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(C) To determine the number of unpaired electrons,we look at the electronic configuration of each ion:$Fe^{3+} = [Ar] 3d^5$ ($5$ unpaired electrons)$M

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$Fe^{3+}$ and $Mn^{2+}$

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(C) To determine the number of unpaired electrons,we look at the electronic configuration of each ion:$Fe^{3+} = [Ar] 3d^5$ ($5$ unpaired electrons)$Mn^{2+} = [Ar] 3d^5$ ($5$ unpaired electrons)$Co^{2+} = [Ar] 3d^7$ ($3$ unpaired electrons)$Sc^{3+} = [Ar] 3d^0$ ($0$ unpaired electrons)$Zn^{2+} = [Ar] 3d^{10}$ ($0$ unpaired electrons)$Mn^{3+} = [Ar] 3d^4$ ($4$ unpaired electrons)Comparing the pairs:Option $A$: $Co^{2+}$ $(3)$ and $Mn^{3+}$ $(4)$ - DifferentOption $B$: $Mn^{2+}$ $(5)$ and $Zn^{2+}$ $(0)$ - DifferentOption $C$: $Fe^{3+}$ $(5)$ and $Mn^{2+}$ $(5)$ - SameOption $D$: $Sc^{3+}$ $(0)$ and $Co^{2+}$ $(3)$ - DifferentTherefore,the pair with the same number of unpaired electrons is $Fe^{3+}$ and $Mn^{2+}$.

Which pair of metal ions from the following has the same number of unpaired electrons?

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