Which statement is correct for Delta G and E_ | vedclass

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(C) An extensive property is a property that depends on the amount of matter present in the system. $\Delta G$ (Gibbs free energy) is proportional to

Vedclass · Accepted Answer

$\Delta G$ is an extensive property and $E_{cell}$ is an intensive property.

Vedclass · Answer

(C) An extensive property is a property that depends on the amount of matter present in the system. $\Delta G$ (Gibbs free energy) is proportional to the number of moles of reactants, making it an extensive property.An intensive property is a property that is independent of the amount of matter present. $E_{cell}$ (electromotive force) is a potential difference that does not depend on the size or amount of the cell, making it an intensive property.Therefore, $\Delta G$ is extensive and $E_{cell}$ is intensive. Thus, option $(C)$ is correct.

Which statement is correct for $\Delta G$ and $E_{cell}$ for a cell reaction?

Similar Questions

Which of the following metals does not liberate $\text{H}_2$ gas by reacting with $\text{HCl}$?

Given the standard electrode potentials: $Fe^{2+}_{(aq)} + 2e^{-} \rightarrow Fe_{(s)}$ $(E^o = -0.44 \ V)$ and $Fe^{3+}_{(aq)} + e^{-} \rightarrow Fe^{2+}_{(aq)}$ $(E^o = 0.77 \ V)$. If $Fe^{2+}$,$Fe^{3+}$,and a piece of $Fe$ are kept together,what happens?

The standard Gibbs energy for the given cell reaction in $kJ \, mol^{-1}$ at $298 \, K$ is $Zn_{(s)} + Cu^{2+}_{(aq)} \to Zn^{2+}_{(aq)} + Cu_{(s)}$,given $E^o = 2 \, V$ at $298 \, K$ [Faraday's constant $F = 96500 \, C \, mol^{-1}$].

Which is the increasing order of reducing power of the following metals on the basis of standard electrode potential? $Ag^{+}/Ag = 0.80 \ V$,$Mg^{2+}/Mg = -2.37 \ V$,$Hg^{2+}/Hg = 0.79 \ V$,$Cr^{3+}/Cr = -0.74 \ V$

Based on the given standard electrode potentials,identify the metal that can be displaced from its salt solution by all other metals listed.
$E^o Zn^{2+}/Zn = -0.76 \ V, E^o Cu^{2+}/Cu = +0.34 \ V$
$E^o Ag^+/Ag = +0.80 \ V, E^o Co^{2+}/Co = -0.28 \ V$

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