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(B) The formula for the percentage of nitrogen in Kjeldahl's method is: $\% 	ext{N} = \frac{1.4 	imes 	ext{Molarity of acid} 	imes 	ext{Basicity

Vedclass · Accepted Answer

$56$

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(B) The formula for the percentage of nitrogen in Kjeldahl's method is: $\% 	ext{N} = \frac{1.4 	imes 	ext{Molarity of acid} 	imes 	ext{Basicity of acid} 	imes 	ext{Volume of acid in mL}}{	ext{Mass of organic compound in g}}$Here,$	ext{Molarity} = 2 \ M$,$	ext{Basicity of } H_2SO_4 = 2$,$	ext{Volume} = 2.5 \ mL$,and $	ext{Mass} = 0.25 \ g$.Substituting the values:$\% 	ext{N} = \frac{1.4 	imes 2 	imes 2 	imes 2.5}{0.25}$$\% 	ext{N} = \frac{1.4 	imes 10}{0.25} = \frac{14}{0.25} = 56$Therefore,the percentage of nitrogen is $56\%$.

While estimating the nitrogen present in an organic compound by Kjeldahl's method,the ammonia evolved from $0.25 \ g$ of the compound neutralized $2.5 \ mL$ of $2 \ M \ H_2SO_4$. The percentage of nitrogen present in the organic compound is $......$

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