(A) When white phosphorus $(P_4)$ is boiled with a concentrated solution of caustic soda $(NaOH)$,it undergoes disproportionation to form phosphine $(

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(A) When white phosphorus $(P_4)$ is boiled with a concentrated solution of caustic soda $(NaOH)$,it undergoes disproportionation to form phosphine $(PH_3)$ and sodium hypophosphite $(NaH_2PO_2)$.The balanced chemical equation is: $P_4 + 3NaOH + 3H_2O \to PH_3 + 3NaH_2PO_2$.Thus,the correct product is phosphine.