Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The colour of coordination complexes arises from $d-d$ transitions,which depend on the magnitude of crystal field splitting $(\Delta)$.
For the same metal ion and the same ligands,the crystal field splitting energy in an octahedral complex $(\Delta_o)$ is significantly larger than in a tetrahedral complex $(\Delta_t)$.
The relationship between them is given by $\Delta_t = \frac{4}{9} \Delta_o$.
Since the energy gap $(\Delta)$ is different,the wavelength of light absorbed $(\Delta E = \frac{hc}{\lambda})$ is different,leading to the observation of different complementary colours for the same metal-ligand system.

Explore More

Similar Questions

Number of complexes with an even number of electrons in $t_{2g}$ orbitals is -
$[Fe(H_2O)_6]^{2+}, [Co(H_2O)_6]^{2+}, [Co(H_2O)_6]^{3+}, [Cu(H_2O)_6]^{2+}, [Cr(H_2O)_6]^{2+}$

What is the color of the $[Ti(H_2O)_6]^{3+}$ complex?

The crystal field stabilisation energy $(CFSE)$ and the spin-only magnetic moment in Bohr Magneton $(BM)$ for the complex $K_3[Fe(CN)_6]$ are,respectively

Which of the following is an incorrectly matched complex?

An ion $M^{2+}$ forms the complexes $[M(H_2O)_6]^{2+}$,$[M(en)_3]^{2+}$,and $[MBr_6]^{4-}$. Match the complex with the appropriate colour.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo