Why does (second)^{2} occur in the unit of ac | vedclass

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(B) Acceleration is defined as the rate of change of velocity with respect to time.$	ext{Acceleration} = \frac{	ext{Change in velocity}}{	ext{Time

Vedclass · Accepted Answer

Because acceleration is the rate of change of velocity with respect to time.

Vedclass · Answer

(B) Acceleration is defined as the rate of change of velocity with respect to time.$	ext{Acceleration} = \frac{	ext{Change in velocity}}{	ext{Time taken}}$The $SI$ unit of velocity is $	ext{meters per second}$ ($m/s$ or $m s^{-1}$) and the $SI$ unit of time is $	ext{second}$ $(s)$.Substituting these units into the formula:$	ext{Unit of acceleration} = \frac{m s^{-1}}{s} = m s^{-2}$Therefore,the $(second)^{2}$ appears in the denominator because velocity is divided by time,resulting in the square of the time unit in the denominator.

Why does $(second)^{2}$ occur in the unit of acceleration?

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