Why is $ICl$ more reactive than $I_2$?

  • A
    $ICl$ is polar while $I_2$ is non-polar.
  • B
    $I-Cl$ bond is weaker than $I-I$ bond.
  • C
    Both $A$ and $B$.
  • D
    None of the above.

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Fluorine with dilute $NaOH$ gives

Assertion $(A)$: The bond dissociation energy increases from $F_2$ to $Cl_2$ and then decreases to $I_2$.
Reason $(R)$: The low bond energy of fluorine is due to the repulsion between the lone pairs of electrons in two fluorine atoms.
The correct option among the following is

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