Why is the alkyl halide shown below not capable of undergoing an $E2$ reaction upon treatment with sodium ethoxide?

  • A
    $Br^-$ is a too poor leaving group.
  • B
    Too much angle strain would be present in the alkene product.
  • C
    Sodium ethoxide is a poor base to use in $E2$ reaction.
  • D
    The $C-H$ and $C-Br$ bonds which need to break cannot achieve an anti-periplanar orientation.

Explore More

Similar Questions

Assertion $A:$ Hydrolysis of an alkyl chloride is a slow reaction but in the presence of $NaI$,the rate of the hydrolysis increases.
Reason $R:$ $I^{-}$ is a good nucleophile as well as a good leaving group.
In the light of the above statements,choose the correct answer from the options given below.

Chlorination of toluene in the presence of light and heat followed by reaction with aqueous $NaOH$ gives ...................

$A$ bromoalkane $X$ reacts with magnesium in dry ether to form compound $Y$. The reaction of $Y$ with methanal followed by hydrolysis yields an alcohol having molecular formula $C_{4}H_{10}O$. The compound $X$ is

An organic compound $A$ $(C_4H_9Cl)$ on reaction with $Na$ in diethyl ether gives a hydrocarbon,which on monochlorination gives only one chloro derivative. $A$ is:

Difficult
View Solution

Which among the following is $NOT$ a feature of $S_N2$ mechanism?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo