Why is there a large difference in the boiling points of butanal and butan$-1-$ol?
The boiling point of butan$-1-$ol is significantly higher than that of butanal because butan$-1-$ol molecules are associated through intermolecular hydrogen bonding.
In contrast,butanal molecules are held together only by weak dipole-dipole interactions.
This strong intermolecular hydrogen bonding in alcohols requires more energy to break,resulting in a higher boiling point compared to aldehydes of similar molecular mass.
In contrast,butanal molecules are held together only by weak dipole-dipole interactions.
This strong intermolecular hydrogen bonding in alcohols requires more energy to break,resulting in a higher boiling point compared to aldehydes of similar molecular mass.
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Similar Questions
Find the major product of the following reaction: $C_6H_5CHO + CH_3CHO \xrightarrow{Ca(OH)_2, \Delta} ?$
Difficult
View SolutionIn the given reaction,
$Cyclohexanone \xrightarrow[(ii) \text{ heat}]{(i) \text{ } OH^-} 'P'$
The number of $\pi$ electrons present in the product $'P'$ is $....$
$Cyclohexanone \xrightarrow[(ii) \text{ heat}]{(i) \text{ } OH^-} 'P'$
The number of $\pi$ electrons present in the product $'P'$ is $....$
Identify the products of the following reaction:
$HCHO + C_6H_5CHO \xrightarrow[ii. \ H_3O^+]{i. \ conc. \ NaOH} ?$
$HCHO + C_6H_5CHO \xrightarrow[ii. \ H_3O^+]{i. \ conc. \ NaOH} ?$
An aldehyde or ketone containing at least one $\alpha-H$ atom reacts with dilute $NaOH$ to form a $\beta-$hydroxy aldehyde or $\beta-$hydroxy ketone. This reaction is known as $—$
Medium
View SolutionConsider the following reaction,where:
$(A)$ The change in the functional group and
$(B)$ The corresponding change in the hybridization from the starting material to the final product are:
$CH_3-C \equiv N \xrightarrow[(ii) \ HI + \text{Red } P]{(i) \ SnCl_2, HCl / H_3O^{+}}$
$(A)$ The change in the functional group and
$(B)$ The corresponding change in the hybridization from the starting material to the final product are:
$CH_3-C \equiv N \xrightarrow[(ii) \ HI + \text{Red } P]{(i) \ SnCl_2, HCl / H_3O^{+}}$
DifficultTS EAMCET 2022
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