With reference to the figure shown below, mat | vedclass

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(C) $1$. From the figure, the angle of incidence $i = 30^\circ$.$2$. According to the law of reflection, the angle of reflection $r = i = 30^\circ$. T

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$a-iii, b-i, c-ii$

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(C) $1$. From the figure, the angle of incidence $i = 30^\circ$.$2$. According to the law of reflection, the angle of reflection $r = i = 30^\circ$. Thus, $(a) \rightarrow (iii)$.$3$. The angle $\alpha$ is the angle between the reflected ray and the mirror surface. Since the normal is perpendicular to the mirror, $\alpha + r = 90^\circ$. Therefore, $\alpha = 90^\circ - 30^\circ = 60^\circ$. Thus, $(b) \rightarrow (i)$.$4$. The angle of deviation $\delta$ is given by $\delta = 180^\circ - (i + r) = 180^\circ - (30^\circ + 30^\circ) = 180^\circ - 60^\circ = 120^\circ$. Thus, $(c) \rightarrow (ii)$.$5$. The correct matching is $a-iii, b-i, c-ii$.

$(a)$ Angle of reflection	$(i)$ $60^\circ$
$(b)$ Value of $\alpha$	(ii) $120^\circ$
$(c)$ Angle of deviation	(iii) $30^\circ$

With reference to the figure shown below, match the following:
$(a)$ Angle of reflection $(i)$ $60^\circ$
$(b)$ Value of $\alpha$ (ii) $120^\circ$
$(c)$ Angle of deviation (iii) $30^\circ$

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With reference to the figure shown below, match the following:$(a)$ Angle of reflection$(i)$ $60^\circ$$(b)$ Value of $\alpha$(ii) $120^\circ$$(c)$ Angle of deviation(iii) $30^\circ$