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(B) From reaction $(I)$,$B$ displaces $A$,so $B > A$.From reaction $(II)$,$A$ reacts with $HCl$ to evolve $H_2$,indicating $A$ is more reactive than $

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$B > A > D > E$

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(B) From reaction $(I)$,$B$ displaces $A$,so $B > A$.From reaction $(II)$,$A$ reacts with $HCl$ to evolve $H_2$,indicating $A$ is more reactive than $H$.From reaction $(III)$,$D$ displaces $E$,so $D > E$.From reaction $(IV)$,$D$ does not evolve $H_2$ with $HNO_3$,suggesting $D$ is less reactive than $A$ (since $A$ evolved $H_2$ with $HCl$).Combining these,we get the order $B > A > D > E$.

With the help of the following reactions,arrange metals $A$,$B$,$D$,and $E$ in decreasing order of their reactivity:
$(I)$ $B + ANO_3 \to BNO_3 + A$
$(II)$ $A + HCl \to ACl + \frac{1}{2}H_2$
$(III)$ $D + ECl \to DCl + E$
$(IV)$ $D + HNO_3 \to H_2$ gas is not evolved

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With the help of the following reactions,arrange metals $A$,$B$,$D$,and $E$ in decreasing order of their reactivity:$(I)$ $B + ANO_3 \to BNO_3 + A$$(II)$ $A + HCl \to ACl + \frac{1}{2}H_2$$(III)$ $D + ECl \to DCl + E$$(IV)$ $D + HNO_3 \to H_2$ gas is not evolved