With the help of the remainder theorem,find t | vedclass

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(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

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$0$

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(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $(x - 1)$,so $a = 1$.To find the remainder,we calculate $p(1)$:$p(1) = (1)^{3} + (1)^{2} - 26(1) + 24$$p(1) = 1 + 1 - 26 + 24$$p(1) = 2 - 26 + 24$$p(1) = -24 + 24 = 0$.Therefore,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 1$.

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