With the help of the remainder theorem,find t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 6$,which can be

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(C) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 6$,which can be written as $x - (-6)$.Therefore,we need to find $p(-6)$.Given $p(x) = x^{3} + x^{2} - 26x + 24$.Substituting $x = -6$ into the polynomial:$p(-6) = (-6)^{3} + (-6)^{2} - 26(-6) + 24$$p(-6) = -216 + 36 + 156 + 24$$p(-6) = -216 + 216$$p(-6) = 0$.Thus,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x + 6$.

Similar Questions

Classify the following polynomial as a polynomial in one variable,two variables,etc.:
$x y + y z + z x$

If $x+y=12$ and $xy=27$,find the value of $x^{3}+y^{3}$.

Expand $\left(\frac{x}{2}-\frac{2}{5}\right)^{2}$.

For $p(x) = x^{3} + 9x^{2} + 26x + 24$,find the value of $p(-2)$.

Show that $2x - 3$ is a factor of $x + 2x^3 - 9x^2 + 12$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module