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(D) The work done in a $P-V$ diagram is equal to the area under the curve with respect to the $V$-axis.In the given figure, the area under the line $A

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$0.3$

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(D) The work done in a $P-V$ diagram is equal to the area under the curve with respect to the $V$-axis.In the given figure, the area under the line $AB$ with respect to the $V$-axis is a trapezoid.The coordinates are $A(10 \, 	ext{kPa}, 10 \, 	ext{cc})$ and $B(30 \, 	ext{kPa}, 25 \, 	ext{cc})$.Since the area is taken with respect to the $V$-axis, the parallel sides are the pressure values $P_A = 10 	imes 10^3 \, 	ext{Pa}$ and $P_B = 30 	imes 10^3 \, 	ext{Pa}$, and the height is the change in volume $\Delta V = (25 - 10) \, 	ext{cc} = 15 	imes 10^{-6} \, 	ext{m}^3$.Work done $W = 	ext{Area} = \frac{1}{2} 	imes (P_A + P_B) 	imes \Delta V$$W = \frac{1}{2} 	imes (10 	imes 10^3 + 30 	imes 10^3) 	imes (25 - 10) 	imes 10^{-6}$$W = \frac{1}{2} 	imes (40 	imes 10^3) 	imes (15 	imes 10^{-6})$$W = 20 	imes 10^3 	imes 15 	imes 10^{-6} = 300 	imes 10^{-3} = 0.3 \, J$.

Work done for the process shown in the figure is ............ $J$

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