Work function (W_0) values of six metals (in | vedclass

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(C) The energy of the incident radiation $(E)$ is calculated using the formula: $E = \frac{hc}{\lambda}$.Substituting the values: $E = \frac{6.62 	im

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$3$

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(C) The energy of the incident radiation $(E)$ is calculated using the formula: $E = \frac{hc}{\lambda}$.Substituting the values: $E = \frac{6.62 	imes 10^{-34} 	imes 3 	imes 10^8}{400 	imes 10^{-9} 	imes 1.6 	imes 10^{-19}} 	ext{ eV} \approx 3.1 	ext{ eV}$.For photoemission to occur,the energy of the incident radiation must be greater than or equal to the work function $(E \ge W_0)$.Conversely,electrons will not be ejected if the work function is greater than the incident energy $(W_0 > E)$.Comparing the given work functions with $3.1 	ext{ eV}$:$Mg (3.7 > 3.1)$,$Cu (4.8 > 3.1)$,and $Ag (4.3 > 3.1)$ have work functions greater than $3.1 	ext{ eV}$.Therefore,$3$ metals will not eject electrons.

Work function $(W_0)$ values of six metals (in $eV$) are given below: $Li: 2.42, Mg: 3.7, Cu: 4.8, Ag: 4.3, K: 2.25, Na: 2.3$. How many of the above metals do not eject the electrons when they are made to strike with radiation of wavelength $400 \text{ nm}$? $(h = 6.62 \times 10^{-34} \text{ Js})$

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