Write about the oxidation reaction of methyl ketone compounds $(R-CO-CH_3)$ by the haloform reaction or write a note on the Haloform test.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Methyl ketones $(R-CO-CH_3)$ are oxidized by sodium hypohalite $(NaOX)$ to the sodium salts of corresponding carboxylic acids having one carbon atom less than that of the carbonyl compound. The methyl group is converted to haloform $(CHX_3)$. This oxidation does not affect a carbon-carbon double bond $(C=C)$,if present in the molecule.
$R-CO-CH_3 + 3NaOX \rightarrow R-COONa + CHX_3 + 2NaOH$
The reaction proceeds in two steps:
$(i)$ $R-CO-CH_3 + 3NaOX \rightarrow R-CO-CX_3 + 3NaOH$
(ii) $R-CO-CX_3 + NaOH \rightarrow R-COONa + CHX_3$
Iodoform reaction with sodium hypoiodite $(NaOI)$ is also used for the detection of the $CH_3CO-$ group or $CH_3CH(OH)-$ group,which produces iodoform ($CHI_3$,yellow precipitate) on oxidation.

Explore More

Similar Questions

What is the product obtained in the reaction of acetaldehyde with semicarbazide?

Identify the symmetrical ketone from the following compounds.

$A$ compound contains an $\alpha$-hydrogen atom and forms a $\beta$-hydroxy aldehyde in the presence of a dilute alkali. When this product is heated with a dilute acid,it yields unsaturated crotonaldehyde. Identify the compound.

Compound $X$ undergoes the following reaction sequence. What is the structure of compound $X$?

In the reaction
$Phenol$ $\xrightarrow[\text{Reimer-Tiemann}]{} X$ $\xrightarrow[(ii) H^+]{(i) NaOH \text{ (conc.)}} Z$
Product $Z$ is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo