Write the bond angle and hybridization type of the water molecule.
(N/A) In the water molecule $(H_2O)$,the oxygen atom is $sp^3$ hybridized.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
Explore More
Similar Questions
Hybridisation of the central atom in $NF_3$ is
Easy
View SolutionThe hybridisation of the central iodine atom in $IF_5$,$I_3^-$,and $I_3^+$ are respectively:
In which of the following molecules/ions $BF_3$,$NO_2^-$,$NH_2^-$ and $H_2O$,the central atom is $sp^2$ hybridised?
DifficultAIPMT 2009
View SolutionWhat is the hybridization state of the central atom in the conjugate base of $NH_4^{+}$ ion?
$XeF_2$ involves which type of hybridisation?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo