Write the formula for the magnetic force acting on a current-carrying wire placed in a uniform magnetic field.

(N/A) The magnetic force $F$ acting on a straight current-carrying wire of length $L$ carrying current $I$ placed in a uniform magnetic field $B$ is given by the vector product:
$F = I(\vec{L} \times \vec{B})$
Where:
$I$ is the current in the wire (in Amperes),
$\vec{L}$ is the length vector of the wire (in meters),directed along the flow of current,
$\vec{B}$ is the uniform magnetic field (in Tesla),
$F$ is the magnetic force (in Newtons).
In terms of magnitude,this can be written as $F = BIL \sin(\theta)$,where $\theta$ is the angle between the direction of the current and the magnetic field.