Write the formula for the magnetic field at the centre of a circular current-carrying loop.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) For a circular loop of radius $R$ carrying a current $I$,the magnetic field $B$ at its centre is given by the formula:
$B = \frac{\mu_0 I}{2R}$
Where:
$B$ is the magnetic field in Tesla $(T)$,
$\mu_0$ is the permeability of free space $(4\pi \times 10^{-7} \ T \cdot m/A)$,
$I$ is the current in Amperes $(A)$,
$R$ is the radius of the loop in meters $(m)$.

Explore More

Similar Questions

Which of the following gives the value of the magnetic field according to Biot-Savart's law?

Two identical circular current loops of radius $R$ carrying equal currents $I$ are placed such that their axes are inclined at $45^\circ$ to each other. The distance from the center of each loop to point $P$ is $\sqrt{3}R$. The resultant magnetic field at $P$ is:

Two infinitely long parallel wires carry equal current in the same direction. The magnetic field at a midpoint between the two wires is

The magnetic field due to a straight conductor of uniform cross section of radius $a$ and carrying a steady current is represented by

The magnetic field at the centre of a current-carrying circular coil is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo