Write four solutions for the following equation: $2x + 5y = 20$.

Given equation: $2x + 5y = 20$.
Rearranging for $y$: $5y = 20 - 2x$,which gives $y = \frac{20 - 2x}{5}$.
$1$. If $x = 0$,then $y = \frac{20 - 2(0)}{5} = \frac{20}{5} = 4$. So,$(0, 4)$ is a solution.
$2$. If $x = 5$,then $y = \frac{20 - 2(5)}{5} = \frac{10}{5} = 2$. So,$(5, 2)$ is a solution.
$3$. If $x = -5$,then $y = \frac{20 - 2(-5)}{5} = \frac{30}{5} = 6$. So,$(-5, 6)$ is a solution.
$4$. If $x = 10$,then $y = \frac{20 - 2(10)}{5} = \frac{0}{5} = 0$. So,$(10, 0)$ is a solution.
Thus,four solutions of the given equation are $(0, 4), (5, 2), (-5, 6),$ and $(10, 0)$.