(N/A) To find the solutions for the equation $2x - 5y = 10$,we can substitute different values for $x$ and solve for $y$,or vice versa.
$1$. If $x = 0$,then $2(0) - 5y = 10 \implies -5y = 10 \implies y = -2$. So,$(0, -2)$ is a solution.
$2$. If $y = 0$,then $2x - 5(0) = 10 \implies 2x = 10 \implies x = 5$. So,$(5, 0)$ is a solution.
$3$. If $x = -5$,then $2(-5) - 5y = 10 \implies -10 - 5y = 10 \implies -5y = 20 \implies y = -4$. So,$(-5, -4)$ is a solution.
$4$. If $y = 2$,then $2x - 5(2) = 10 \implies 2x - 10 = 10 \implies 2x = 20 \implies x = 10$. So,$(10, 2)$ is a solution.
Thus,four solutions are $(0, -2), (5, 0), (-5, -4), (10, 2)$.