Write four solutions for the following equation: $5x + 3y = 16$.

(N/A) To find the solutions for the linear equation $5x + 3y = 16$,we can assign arbitrary values to $x$ and solve for $y$ using the formula $y = \frac{16 - 5x}{3}$.
$1$. If $x = 2$,then $y = \frac{16 - 5(2)}{3} = \frac{16 - 10}{3} = \frac{6}{3} = 2$. Solution: $(2, 2)$.
$2$. If $x = 5$,then $y = \frac{16 - 5(5)}{3} = \frac{16 - 25}{3} = \frac{-9}{3} = -3$. Solution: $(5, -3)$.
$3$. If $x = -1$,then $y = \frac{16 - 5(-1)}{3} = \frac{16 + 5}{3} = \frac{21}{3} = 7$. Solution: $(-1, 7)$.
$4$. If $x = -4$,then $y = \frac{16 - 5(-4)}{3} = \frac{16 + 20}{3} = \frac{36}{3} = 12$. Solution: $(-4, 12)$.