Write the homolytic and heterolytic fission of the $C-Br$ bond in $CH_3CH_2Br$.

(N/A) $1$. Homolytic Fission: In this process,the shared pair of electrons in the $C-Br$ bond is divided equally between the two atoms,resulting in the formation of free radicals.
$CH_3CH_2-Br \xrightarrow{\text{Homolytic fission}} CH_3CH_2^{\bullet} + Br^{\bullet}$
(Ethyl free radical) (Bromine free radical)
$2$. Heterolytic Fission: In this process,the shared pair of electrons in the $C-Br$ bond is transferred to the more electronegative atom $(Br)$,resulting in the formation of ions.
$CH_3CH_2-Br \xrightarrow{\text{Heterolytic fission}} CH_3CH_2^{+} + Br^{-}$
(Ethyl carbocation) (Bromide ion)