Write structures of various carbocations that can be obtained from $2-$methylbutane. Arrange these carbocations in order of increasing stability.

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(N/A) $2-$methylbutane $(CH_3-CH(CH_3)-CH_2-CH_3)$ has four different sets of equivalent $H$ atoms.
Removal of one hydrogen from each set gives four different carbocations:
$(a) (CH_3)_2CH-CH_2-CH_2^+ \text{ (primary } 1^{\circ} \text{ carbocation)}$
$(b) (CH_3)_2C^+-CH_2-CH_3 \text{ (tertiary } 3^{\circ} \text{ carbocation)}$
$(c) CH_3-CH^+-CH(CH_3)_2 \text{ (secondary } 2^{\circ} \text{ carbocation)}$
$(d) ^+CH_2-CH(CH_3)-CH_2-CH_3 \text{ (primary } 1^{\circ} \text{ carbocation)}$
Stability order of carbocations is $3^{\circ} > 2^{\circ} > 1^{\circ}$.
Comparing the two $1^{\circ}$ carbocations $(a)$ and $(d)$,$(a)$ is more stable than $(d)$ because the alkyl group attached to the positively charged carbon in $(a)$ is $(CH_3)_2CH-CH_2-$,which provides a stronger inductive effect than the group in $(d)$.
Thus,the increasing order of stability is: $(d) < (a) < (c) < (b)$.

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Which of the following carbocations will undergo rearrangement?

Stability order of the following carbocations is:
$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$
$(ii)$ $CH_3-CH^{+}-CH_3$
$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$
$(iv)$ $Ph-CH^{+}-CH_3$

Which of the following are secondary radicals?
$(1) \ CH_3 - \dot{C}H - C_2H_5$
$(2) \ CH_2 = \dot{C} - CH_3$
$(3) \ CH_2 = CH - \dot{C}H_2$
$(4) \ (CH_3)_2 \dot{C}H$

The correct order of stability for the following carbanions is:
$CH_2=CH^{-}, CH_3-CH_2^{-}, CH\equiv C^{-}$

The stability of the carbocations follows the order:

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