Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$
(N/A) The addition of $HBr$ to alkenes follows Markovnikov's rule,where the electrophile $(H^+)$ adds to the carbon with more hydrogen atoms,and the nucleophile $(Br^-)$ adds to the carbon with fewer hydrogen atoms.
$(1)$ For $CH_3CH = CHCH_3 + HBr \to CH_3CH_2-CH(Br)-CH_3$ ($2$-Bromobutane).
$(2)$ For $CH_3-C(CH_3)=CH_2 + HBr \to CH_3-C(Br)(CH_3)-CH_3$ ($2$-Bromo-$2$-methylpropane).
$(1)$ For $CH_3CH = CHCH_3 + HBr \to CH_3CH_2-CH(Br)-CH_3$ ($2$-Bromobutane).
$(2)$ For $CH_3-C(CH_3)=CH_2 + HBr \to CH_3-C(Br)(CH_3)-CH_3$ ($2$-Bromo-$2$-methylpropane).
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