Describe the procedure to demonstrate that the rate of loss of heat from a hot body is directly dependent on the temperature difference between the body and its surroundings.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $1$. Take approximately $300 \ ml$ of water in a calorimeter equipped with a stirrer and cover it with a lid having two holes.
$2$. Insert a thermometer through one hole in the lid,ensuring the bulb is fully immersed in the water. Record the initial reading,$T_{1}$,which represents the temperature of the surroundings.
$3$. Heat the water in the calorimeter until it reaches a temperature approximately $40^{\circ} C$ above the room temperature (surroundings temperature).
$4$. Remove the heat source to stop heating the water.
$5$. Start a stopwatch and record the temperature of the water at fixed intervals (e.g.,every one minute) while stirring gently.
$6$. Continue recording the temperature $(T_{2})$ until the water cools down to about $5^{\circ} C$ above the surroundings temperature.
$7$. Plot a graph with the temperature difference $\Delta T = T_{2} - T_{1}$ on the $y$-axis and the corresponding time $t$ on the $x$-axis.
$8$. From the graph,you will observe that the cooling rate is initially high and decreases as the body's temperature approaches the surroundings temperature. This confirms that the rate of heat loss depends on the temperature difference between the body and its surroundings.

Explore More

Similar Questions

Two spheres have a radius ratio of $1:2$ and a density ratio of $2:1$. They have the same specific heat. If they are heated to the same temperature and placed in the same environment,what is the ratio of their rate of cooling?

It takes $10$ minutes to cool a liquid from $61^{\circ} C$ to $59^{\circ} C$. If the room temperature is $30^{\circ} C$,then the time taken in cooling from $51^{\circ} C$ to $49^{\circ} C$ is .......... $min$.

Difficult
View Solution

$A$ body takes $4\, \text{min}$ to cool from $61^{\circ} \text{C}$ to $59^{\circ} \text{C}$. If the temperature of the surroundings is $30^{\circ} \text{C}$,the time taken by the body to cool from $51^{\circ} \text{C}$ to $49^{\circ} \text{C}$ is $....\, \text{min}$.

$A$ cup of coffee cools from $150^{\circ} F$ to $144^{\circ} F$ in $1 \ min$ in a room at a temperature of $72^{\circ} F$. How much time will the coffee take to cool from $110^{\circ} F$ to $104^{\circ} F$ in the same room (in $min$)?

$A$ suspended sphere has density $d$ and specific heat $s$. The radius of the sphere is $r$. The temperature difference between the sphere and the surroundings $(\Delta \theta)$ is very small. If the temperature of the surroundings is $\theta_0$,then the rate of cooling of the sphere will be .......

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo