Write the products of the following reactions:
$(i)$ $C_6H_5CH=CH_2 + HBr \rightarrow$
(ii) $CH_3-CH_2-CH=CH_2 + HCl \rightarrow$
(iii) $C_6H_5CH_2-CH=CH_2 + HBr \xrightarrow{\text{Peroxide}}$

(N/A) $(i)$ According to Markovnikov's rule,the addition of $HBr$ to styrene $(C_6H_5CH=CH_2)$ gives $C_6H_5CH(Br)CH_3$ ($1$-phenylethyl bromide).
(ii) According to Markovnikov's rule,the addition of $HCl$ to but$-1-$ene $(CH_3-CH_2-CH=CH_2)$ gives $CH_3-CH_2-CHCl-CH_3$ ($2$-chlorobutane).
(iii) In the presence of peroxide,the addition of $HBr$ to $3-$phenylprop$-1-$ene $(C_6H_5CH_2-CH=CH_2)$ follows anti-Markovnikov addition,giving $C_6H_5CH_2-CH_2-CH_2Br$ ($3$-phenylpropyl bromide).