State whether the following statement is True or False and justify your answer:
$A$ cone,a hemisphere,and a cylinder stand on equal bases and have the same height. The ratio of their volumes is $1: 2: 3$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(TRUE) Let the radius of the base of the cone,hemisphere,and cylinder be $r$. Since they stand on equal bases,their radii are equal.
Given that they have the same height,and the height of a hemisphere is equal to its radius $(r)$,the height of the cone and the cylinder must also be $r$.
$1$. Volume of the cone $(V_1)$: $V_1 = \frac{1}{3} \pi r^2 h = \frac{1}{3} \pi r^2 (r) = \frac{1}{3} \pi r^3$.
$2$. Volume of the hemisphere $(V_2)$: $V_2 = \frac{2}{3} \pi r^3$.
$3$. Volume of the cylinder $(V_3)$: $V_3 = \pi r^2 h = \pi r^2 (r) = \pi r^3 = \frac{3}{3} \pi r^3$.
Comparing the volumes: $V_1 : V_2 : V_3 = \frac{1}{3} \pi r^3 : \frac{2}{3} \pi r^3 : \frac{3}{3} \pi r^3 = 1 : 2 : 3$.
Thus,the ratio of their volumes is $1 : 2 : 3$. The statement is True.

Explore More

Similar Questions

The ratio of the radius and slant height of a cone is $3:5$ and its curved surface area is $423.9 \, cm^2$. Find its volume. $(\pi = 3.14)$ (in $cm^3$)

Difficult
View Solution

Surface area of a cuboid = $\ldots \ldots \ldots$

Write True or False and justify your answer in each of the following: If a sphere is inscribed in a cube,then the ratio of the volume of the cube to the volume of the sphere will be $6: \pi$.

The curved surface area of a cylinder is $4400 \, cm^2$ and its base has a radius of $14 \, cm$. Find the volume of the cylinder in $cm^3$.

The volume of a cube is $3375\, cm^{3}$. Find its edge and total surface area.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo