Xenon reacts with fluorine at 873 K and 7 b | vedclass

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(A) $XeF_4$ is obtained by heating a mixture of xenon and fluorine in the molar ratio of $1: 5$ at $873 \ K$ and $7 \ bar$ pressure in an enclosed nic

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$1: 5$

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(A) $XeF_4$ is obtained by heating a mixture of xenon and fluorine in the molar ratio of $1: 5$ at $873 \ K$ and $7 \ bar$ pressure in an enclosed nickel vessel for a few hours. The reaction proceeds as: $Xe_{(g)} + 2 \ F_{2(g)} \xrightarrow{873 \ K, 7 \ bar} XeF_4$ The extra fluorine is added to ensure the complete conversion of xenon to $XeF_4$.

Xenon reacts with fluorine at $873 \ K$ and $7 \ bar$ to form $XeF_4$. In this reaction, the ratio of xenon and fluorine required is

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