Zener breakdown in a semiconductor diode occurs when

  • A
    Forward current exceeds a certain value
  • B
    Reverse bias exceeds a certain value
  • C
    Forward bias exceeds a certain value
  • D
    Potential barrier is reduced to zero

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Manufacturers supply a zener diode with zener voltage $V_{z}=5.6 \, V$ and maximum power dissipation $P_{z \max }=\frac{1}{4} \, W$. This zener diode is used in the following circuit. Calculate the minimum value of the resistance $R_s$ in the circuit so that the zener diode will not burn when the input voltage is $V_{in}=10 \, V$. (in $\Omega$)

$A$ Zener diode in the circuit shown has a knee current of $5\,mA$ and a maximum allowed power dissipation of $300\,mW$. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage $V_0$ constant at $6\,V$?

Write a short note on a Zener diode.

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In the diagram shown,the Zener diode has a reverse breakdown voltage of $V_Z$. The current through the load resistance $R_L$ is $I_L$. The current through the Zener diode is

In the given circuit,the current through the Zener diode is.....$mA$.

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