Zero value of CFSE is observed in which of th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $CFSE$ (Crystal Field Stabilization Energy) for an octahedral complex is calculated as $CFSE = (-0.4n_{t_{2g}} + 0.6n_{e_g}) \Delta_o$. For $C

Vedclass · Accepted Answer

$[FeF_6]^{3-}$

Vedclass · Answer

(D) The $CFSE$ (Crystal Field Stabilization Energy) for an octahedral complex is calculated as $CFSE = (-0.4n_{t_{2g}} + 0.6n_{e_g}) \Delta_o$. For $CFSE$ to be zero,the configuration must be $d^0$,$d^5$ (high spin),or $d^{10}$. Let us analyze the oxidation states and $d$-electron configurations: $A$: $[Cr(H_2O)_6]^{3+}$ $ightarrow Cr^{3+} (d^3)$ $ightarrow CFSE = -1.2 \Delta_o$. $B$: $[CoF_6]^{3-}$ $ightarrow Co^{3+} (d^6)$ $ightarrow 	ext{High spin } t_{2g}^4 e_g^2$ $ightarrow CFSE = -0.4 \Delta_o$. $C$: $[MnF_6]^{2-}$ $ightarrow Mn^{4+} (d^3)$ $ightarrow CFSE = -1.2 \Delta_o$. $D$: $[FeF_6]^{3-}$ $ightarrow Fe^{3+} (d^5)$ $ightarrow 	ext{High spin } t_{2g}^3 e_g^2$ $ightarrow CFSE = (-0.4 	imes 3 + 0.6 	imes 2) \Delta_o = (-1.2 + 1.2) \Delta_o = 0$. Thus,$[FeF_6]^{3-}$ has a $CFSE$ of zero.

Zero value of $CFSE$ is observed in which of the following complexes?

Similar Questions

The degenerate orbitals of $[Cr(H_2O)_6]^{3+}$ are

Which of the following is a weak field ligand?

The crystal field stabilization energy for a high spin $d^4$ octahedral complex is:

For an octahedral complex of $Co$ $(Z = 27)$,which of the following has the highest value of $\Delta_0$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module