Zinc $(II)$ ion on reaction with $NaOH$ first gives a white precipitate which dissolves in excess of $NaOH$ due to the formation of:

  • A
    $ZnO$
  • B
    $Zn(OH)_2$
  • C
    $[Zn(OH)_4]^{2-}$
  • D
    $[Zn(H_2O)_4]^{2+}$

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Similar Questions

The atomic radii of alkali metals $(M)$ lie in the order $Li < Na < K < Rb$,but the radii of $M^{+}$ ions in aqueous solution lie in the reverse order $Li^{+} > Na^{+} > K^{+} > Rb^{+}$. What is the reason for this reverse order (on going from $Li$ to $Rb$)?

Which of the following properties is $NOT$ an anomalous property of $Li$?

The alkali metal with the lowest $E^{\circ}_{M^{+}/M} (V)$ is $X$ and the alkali metal with the highest $E^{\circ}_{M^{+}/M} (V)$ is $Y$. Then $X$ and $Y$ are respectively:

$A$ $s$-block element $(M)$ reacts with oxygen to form an oxide of the formula $MO_{2}$. The oxide is pale yellow in colour and paramagnetic. The element $(M)$ is:

The main oxides formed on combustion of $Li, Na$ and $K$ in excess of air are,respectively:

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