Zinc on reaction with concentrated nitric acid gives an oxide of nitrogen $(A)$. Zinc with dilute nitric acid gives another oxide of nitrogen $(B)$. Oxidation numbers of nitrogen in $(A)$ and $(B)$ are respectively:

  • A
    $+4, +1$
  • B
    $+4, +2$
  • C
    $+2, +4$
  • D
    $+1, +4$

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