A sample of [Cu(NH_3)_4]SO_4 contains 2.4 tim | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 \ mol$ of the compound contains $4 \ mol$ of $NH_3$ molecules.First,calculate the total

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(D) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 \ mol$ of the compound contains $4 \ mol$ of $NH_3$ molecules.First,calculate the total moles of $NH_3$ molecules in the sample:$	ext{Moles of } NH_3 = \frac{2.4 	imes 10^{24}}{6.022 	imes 10^{23}} \approx 4 \ mol$.Since $4 \ mol$ of $NH_3$ are present in $1 \ mol$ of $[Cu(NH_3)_4]SO_4$,the number of moles of the compound is $\frac{4 \ mol}{4} = 1 \ mol$.

$A$ sample of $[Cu(NH_3)_4]SO_4$ contains $2.4 \times 10^{24}$ ammonia molecules. The moles of $[Cu(NH_3)_4]SO_4$ in the given sample will be:

Similar Questions

If a gaseous mixture contains $20\%$ $H_2$ by weight,what is the number of moles of $H_2$ in $100 \ g$ of the mixture (in $mol$)?

Which of the following contains the maximum number of molecules?

Which among the following elements has the highest number of atoms in $1 \ g$ each? (Atomic masses: $Au=197, Na=23, Cu=63.5, Fe=56$)

The number of moles of sodium oxide in $620 \ g$ of it is ................ $moles$.

What is the number of moles of oxygen atoms and the number of moles of $N$ atoms respectively present in one mole of thymine?

Vedclass Test Series

Exam Paper Generator

Online Exam Module