₹ 1980 is divided among A,B,and C such that h | vedclass

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(A) Let the parts of $A$,$B$,and $C$ be $A$,$B$,and $C$ respectively.According to the problem,$\frac{1}{2} A = \frac{1}{3} B = \frac{1}{6} C = k$ (whe

Vedclass · Accepted Answer

$540$

Vedclass · Answer

(A) Let the parts of $A$,$B$,and $C$ be $A$,$B$,and $C$ respectively.According to the problem,$\frac{1}{2} A = \frac{1}{3} B = \frac{1}{6} C = k$ (where $k$ is a constant).Therefore,$A = 2k$,$B = 3k$,and $C = 6k$.The total sum is $A + B + C = 1980$.Substituting the values: $2k + 3k + 6k = 1980$.$11k = 1980$.$k = \frac{1980}{11} = 180$.$B$'s part is $3k = 3 	imes 180 = ₹ 540$.

₹ $1980$ is divided among $A$,$B$,and $C$ such that half of $A$'s part,one-third of $B$'s part,and one-sixth of $C$'s part are equal. What is $B$'s part (in ₹)?

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