₹ 1500 is invested at a rate of 10 % simple i | vedclass

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(A) The simple interest on ₹ $1500$ invested at a rate of $10 \%$ per annum for $5$ years is:Interest $= \frac{P 	imes R 	imes T}{100} = \frac{1500

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$6 \frac{1}{9}$ years

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(A) The simple interest on ₹ $1500$ invested at a rate of $10 \%$ per annum for $5$ years is:Interest $= \frac{P 	imes R 	imes T}{100} = \frac{1500 	imes 10 	imes 5}{100} = ₹ 750$After $5$ years,the interest is added to the principal. Therefore,the new principal $= ₹ 1500 + 750 = ₹ 2250$.The target amount is ₹ $2500$. The remaining interest required is $₹ 2500 - 2250 = ₹ 250$.Using the simple interest formula for the remaining time $T$:$250 = \frac{2250 	imes 10 	imes T}{100}$$250 = 225 	imes T$$T = \frac{250}{225} = \frac{10}{9}$ years.Total time $= 5 + \frac{10}{9} = 5 + 1 \frac{1}{9} = 6 \frac{1}{9}$ years.

₹ $1500$ is invested at a rate of $10 \%$ simple interest,and the interest is added to the principal after every $5$ years. In how many years will it amount to ₹ $2500$?

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